2.2 Unit Circle

Activity 2.2.2

Convert each of the following quantities to the alternative measure: degrees to radians or radians to degrees.

a. [latex]30^{\circ}[/latex]

b. [latex]\frac{2\pi}{3}[/latex] radians

c. [latex]\frac{5\pi}{4}[/latex] radians

d. [latex]240^{\circ}[/latex]

e. [latex]17^{\circ}[/latex]

f. [latex]2[/latex] radians

 

Show Solution

a. [latex]30^{\circ}\cdot \frac{\pi}{180}=\frac{\pi}{6}[/latex]

b. [latex]\frac{2\pi}{3}\cdot \frac{180}{\pi}=120^{\circ}[/latex]

c. [latex]\frac{5\pi}{4}\cdot \frac{180}{\pi}=225^{\circ}[/latex]

d. [latex]240^{\circ}\cdot \frac{\pi}{180}=\frac{4\pi}{3}[/latex]

e. [latex]17^{\circ}\cdot \frac{\pi}{180}=\frac{17\pi}{180}[/latex]

f. [latex]2\cdot \frac{180}{\pi}=\frac{360}{\pi}^{\circ}[/latex]

 

Activity 2.2.4

Determine each of the following values or points exactly.

a. In a circle of radius 11, the arc length intercepted by a central angle of [latex]\frac{5\pi}{3}[/latex].

b. In a circle of radius 3, the central angle measure that intercepts an arc of length [latex]\frac{\pi}{4}[/latex].

c. The radius of the circle in which an angle of [latex]\frac{7\pi}{6}[/latex] intercepts an arc of length [latex]\frac{\pi}{2}[/latex].

d. The exact coordinates of the point on the circle of radius 5 that lies [latex]\frac{25\pi}{6}[/latex] units counterclockwise along the circle from [latex](5,0)[/latex].

 

Show Solution

Use formula [latex]s=r\cdot \theta[/latex].

a. [latex]r=11[/latex], [latex]\theta=\frac{5\pi}{3}[/latex]

[latex]s=11\cdot \frac{5\pi}{3}= \frac{55\pi}{3}[/latex]

b. [latex]r=3[/latex], [latex]s=\frac{\pi}{4}[/latex]

[latex]\frac{\pi}{4}=3 \cdot \theta[/latex]

[latex]\theta=\frac{\pi}{12}[/latex]

c. [latex]\theta=\frac{7\pi}{6}[/latex], [latex]s=\frac{\pi}{2}[/latex]

[latex]\frac{\pi}{2}=r\cdot \frac{7\pi}{6}[/latex]

[latex]r=\frac{3}{7}[/latex]

d. [latex]r=5[/latex], [latex]s=\frac{25\pi}{6}[/latex]

[latex]\frac{25\pi}{6}=5\cdot \theta[/latex]

[latex]\theta=\frac{5\pi}{6}[/latex]

Then the coordinate for a circle of radius 5 at this angle is [latex](-\frac{5\sqrt{3}}{2}, \frac{5}{2})[/latex].

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Pre-Calculus Problem Sets Copyright © by Sherri Spriggs and Marcela Gutierrez. All Rights Reserved.

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